There are many questions are floating on internet that AJAX code doesnot work for Mozilla FireFox. And interesting there is no such exact solution for this. Some days back I have also posted one article on my blog regarding one simple tutorial on Ajax and it was very fine with IE. One day I got one comment that my tutorial is not working for Firefox. I asked this question to one of my friend and she gave the solution.
Thanks MP.Complete Example:
[
Please follow my prior posting to setup this tutorial]
1. ShowStudentInfo.jsp (C:\Ajax_workspace\blog_demo\WebContent\ShowStudentInfo.jsp)
2. StudentInfo.java (C:\Ajax_workspace\blog_demo\src\StudentInfo.java) This is a servlet.
ShowStudentInfo.jsp
<html>
<head>
<title>Binod Java Solution AJAX</title>
<script type="text/javascript">
var request; function getName(){
var roll = document.getElementById("roll").value;
var url = "http://localhost:8080/blog_demo/StudentInfo?roll="+roll;
if(window.ActiveXObject){
request = new ActiveXObject("Microsoft.XMLHTTP");
}
else if(window.XMLHttpRequest){
request = new XMLHttpRequest();
}
request.onreadystatechange = showResult;
request.open("POST",url,true);
request.send(null);
}
function showResult(){
if(request.readyState == 4){
if ( request.status == 200 ) {
var response = request.responseXML;
var students = response.getElementsByTagName("Student");
var student = students[0];
document.getElementById("NamelH1").innerHTML = student.getElementsByTagName("Name")[0].childNodes[0].data;
document.getElementById("HostelH1").innerHTML = student.getElementsByTagName("Hostel")[0].childNodes[0].data;
document.getElementById("ContactH1").innerHTML = student.getElementsByTagName("Contact")[0].childNodes[0].data;
}
}
}
</script>
</head>
<body>
<h2>GET STUDENT INFO</h2>
<br>
Enter Roll Number
<input type="text" id="roll">
<input type="button" value="Get Name" onclick="getName();" />
<br>
Name :
<span id="NamelH1"></span>
<br>
Hostel :
<span id="HostelH1"></span>
<br>
Contact :
<span id="ContactH1"></span>
<br>
</body>
</html>
StudentInfo.java
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class StudentInfo extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet {
static final long serialVersionUID = 1L;
public StudentInfo() { super(); }
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doPost(request,response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String roll = request.getParameter("roll");
PrintWriter out = response.getWriter();
response.setContentType("text/xml");
System.out.println(getResult(roll)); out.println(getResult(roll));
}
public String getResult(String roll){
String name = "";
String hostel = "";
String contact = "";
if(roll.equalsIgnoreCase("110")){
name = "Binod Kumar Suman"; hostel = "Ganga"; contact = "999999999";
} else if(roll.equalsIgnoreCase("120")){
name = "Pramod Kumar Modi"; hostel = "Godawari"; contact = "111111111111";
} else{ name = "Roll Number not found"; }
String result = "<Students>";
result += "<Student>"; result += "<Name>" + name + "</Name>";
result += "<Hostel>" +hostel + "</Hostel>";
result += "<Contact>" +contact + "</Contact>";
result += "</Student>"; result += "</Students>";
return result;
}
}
This code also work well with IE.
